2x^2+50x-336=0

Solution for 2x^2+50x-336=0 equation:

2x^2+50x-336=0

a = 2; b = 50; c = -336;
Δ = b2-4ac
Δ = 502-4·2·(-336)
Δ = 5188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5188}=\sqrt{4*1297}=\sqrt{4}*\sqrt{1297}=2\sqrt{1297}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{1297}}{2*2}=\frac{-50-2\sqrt{1297}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{1297}}{2*2}=\frac{-50+2\sqrt{1297}}{4}
$